vault backup: 2026-10-05 08:52:57

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ben committed 2026-10-05 08:52:57 -07:00
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commit 074301848f
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+6 -1
@@ -31,8 +31,13 @@
- There can also be non-trivial solutions
To find when the system $$\begin{gathered} 3x_{1} + 6x_{2} = 2 \\ hx_{1} + 12x_{2} = k \end{gathered}$$ has no solutions
$$\begin{bmatrix}
3 & 6 & 2 \\ h & 12 & k
\end{bmatrix} \sim \begin{bmatrix}
h & 2h & \frac{2h}{3} \\ h & 12 & k
\end{bmatrix} \sim \begin{bmatrix}
h & 2h & \frac{2h}{3} \\ 0 & 12 - 2h & k - \frac{2h}{3}
\end{bmatrix} $$
There are no solutions the system of equations when there is no pivot in a row and the value on the right is not equal to zero (if the value on the right is also equal to zero than that equation is essentially $0=0$ which is always true).
This means that there are no solutions when $$12-2h = 0 \to h=6$$ and $$k-\frac{2h}{3} \ne 0$$