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PCB Design/Music Player/Process.md

@@ -47,3 +47,5 @@ To limit the current of the backlight for the display series resistors are neede
 $$R = \frac{{V_{in} - V_{f}}}{I_{f}}$$
 is used which gives the current limiting resistor needed for a LED. The display used has a LED voltage of 3.0V and will be supplied with 3.3V. It also typically draws 160 mA of current. Plugging in these values gives
 $$R = \frac{{3.3 - 3.0}}{0.16} = 1.875 \Omega$$
+For a standard value a $2.0  \Omega$ resistor will be used. This may make the display a little bit less bright but won't change it very much.Vs - Vf) / If using the maximum forward voltage:
+### Backlight Control