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vault backup: 2026-06-26 18:33:26

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ben committed 2026-06-26 18:33:26 -07:00
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PCB Design/Music Player/Process.md
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@@ -47,3 +47,5 @@ To limit the current of the backlight for the display series resistors are neede
$$R = \frac{{V_{in} - V_{f}}}{I_{f}}$$ $$R = \frac{{V_{in} - V_{f}}}{I_{f}}$$
is used which gives the current limiting resistor needed for a LED. The display used has a LED voltage of 3.0V and will be supplied with 3.3V. It also typically draws 160 mA of current. Plugging in these values gives is used which gives the current limiting resistor needed for a LED. The display used has a LED voltage of 3.0V and will be supplied with 3.3V. It also typically draws 160 mA of current. Plugging in these values gives
$$R = \frac{{3.3 - 3.0}}{0.16} = 1.875 \Omega$$ $$R = \frac{{3.3 - 3.0}}{0.16} = 1.875 \Omega$$
For a standard value a $2.0 \Omega$ resistor will be used. This may make the display a little bit less bright but won't change it very much.Vs - Vf) / If using the maximum forward voltage:
### Backlight Control