vault backup: 2026-06-24 17:31:21

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ben committed 2026-06-24 17:31:21 -07:00
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@@ -24,4 +24,4 @@ Now calculating for $I_{PEAK}$ using the values
- $\eta = 0.9$ (efficiency assumption stated in datasheet) - $\eta = 0.9$ (efficiency assumption stated in datasheet)
$$I_{PEAK} = \frac{3.3}{0.9 * (1 - 0.302)} + \frac{{2.304 * 0.302}}{2 * 2.5 * 1.5} = 5.346$$ $$I_{PEAK} = \frac{3.3}{0.9 * (1 - 0.302)} + \frac{{2.304 * 0.302}}{2 * 2.5 * 1.5} = 5.346$$
The datasheet states to pick an inductor with a saturation current 20% higher than the calculated value which would mean $$I_{sat} \geq 6.415$$ The datasheet states to pick an inductor with a saturation current 20% higher than the calculated value which would mean $$I_{sat} \geq 6.415$$
The [] The [EXLA1V0402-1R5-R](https://www.digikey.com/en/products/detail/eaton-electronics-division/EXLA1V0402-1R5-R/16893520) has a saturation current of 6.7A which should be a good value for this application. The DC resistance is also low and comparable to the options listed in the datasheet.