From 4c7dc9473ae3df6c1f3f3b5553b778aa9e0070d4 Mon Sep 17 00:00:00 2001 From: ben-jaynes <1btjaynes@gmail.com> Date: Wed, 24 Jun 2026 17:11:15 -0700 Subject: [PATCH] vault backup: 2026-06-24 17:11:15 --- PCB Design/Music Player/Process.md | 17 +++++++++++++++++ 1 file changed, 17 insertions(+) create mode 100644 PCB Design/Music Player/Process.md diff --git a/PCB Design/Music Player/Process.md b/PCB Design/Music Player/Process.md new file mode 100644 index 0000000..0a7f7b0 --- /dev/null +++ b/PCB Design/Music Player/Process.md @@ -0,0 +1,17 @@ +#pcb/musicplayer #pcb +- - - + +## TPS63020 +### Choosing an Inductor +The equations needed to find the peak current in steady state operation are +Duty cycle boost: $$D=\frac{{V_{OUT} - V_{IN}}}{V_{OUT}}$$ +and peak current: $$I_{PEAK} = \frac{I_{out}}{\eta * (1 - D)} + \frac{{V_{IN} * D}}{2 * f * L}$$ +where +- $D$ = duty cycle in boost mode +- $f$ = converter switching frequency +- $L$ = inductor value +- $\eta$ = estimated converter efficiency +(This is taken from section 8.2.2.2 of the datasheet) + +First, to calculate the duty cycle boost we can plug in the output voltage (3.3V) and the "minimum input voltage in boost mode" which for the BQ25985 is listed as 2.304V +$$D = \frac{{3.3 - 2.304}}{3.3} = 0.302$$