vault backup: 2026-10-07 11:54:31
This commit is contained in:
1 parent
0e3d1ce63e
commit
5696f3e8f5
3 files changed
+670
-198
No files matched your search
+11
-1
@@ -5,5 +5,15 @@ $$\begin{gather}
|
||||
a\leq r\leq b \\ \alpha \leq \theta \leq \beta
|
||||
\end{gather}$$
|
||||
|
||||
![[PolarRegion.excalidraw]]
|
||||
|
||||
if a function is defined as $f(x,)$
|
||||
if a function is defined as $f(x,y)$ and the region it is integrated over is polar the integral will often look similar to
|
||||
$$\int_{\alpha}^\beta \int_{a}^b f(r\cos(\theta), r\sin(\theta))r \ dr d\theta$$
|
||||
|
||||
|
||||
Find the volume of the solid below $z=1-x^2-y^2$ and above the first quadrant on the xy plane
|
||||
|
||||
rearranging the equation gives $x^2+y^2=1-z$ which shows that each horizontal slice of the function is a circle centered at $(0,0)$ with a radius of $\sqrt{ 1-z }$
|
||||
|
||||
since the slice of the equation at $z=0$ forms the circle $x^2+y^2=1$ the bounds
|
||||
$$$$
|
||||
Reference in new issue
Block a user