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College/AU 26/MATH 208 (Matrix Algebra)/Chapter 1.2 Notes.md

@@ -22,7 +22,7 @@
 	- 1. multiply each nonzero row by the inverse of the pivot so every pivot is 1
 	- 2. manipulate so every pivot only has zeros above it
 	- This means that leading variables are only in the equations that they lead
-	- This puts the matrix in reduced echelon form
+	- This puts the matrix in **reduced echelon form**
 - Homogeneous linear system
 	- when the $b_{n}$ term of each equation is zero
 	- There is a "trivial solution" where each variable equals zero