vault backup: 2026-10-05 11:54:11

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ben committed 2026-10-05 11:54:11 -07:00
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@@ -12,3 +12,7 @@ This can be extended to more general domains that are not rectangles such as $[a
Example: Example:
finding the volume under the function $f(x,y) = xy$ over the domain bound by finding the volume under the function $f(x,y) = xy$ over the domain bound by
$$\begin{gathered} 1<x<2 \\[1.5ex] x < y < x^2 \end{gathered}$$ $$\begin{gathered} 1<x<2 \\[1.5ex] x < y < x^2 \end{gathered}$$
We can think of finding the volume of the solid by using slices parallel to the $YZ$ plane. With the domain provided this area can be found with
$$ Area(x^*)=\int_{x}^{x^2}x^*ydy$$
Since $x$ is bound by $1<x<2$ the double integral to find the volume can be written as
$$\begin{gather} \int_{1}^2 \left[ \int_{x}^{x^2}xy \ dy \right] dx \\[1.5ex] \int_{1}^2 \left[ \int_{x}^{x^2} \frac{xy^2}{2} \right] dx \end{gather}$$