#uw/class/math208 #uw/notes - - - > [!abstract] Definition > if $\{\mathbf{u}_{1}, \mathbf{u}_{2}, \dots, \mathbf{u}_{m}\}$ is a set of vectors in $\mathbf{R}^n$ then the span of the set is given as $\text{span}\{\mathbf{u_{1}}, \mathbf{u_{2}}, \dots, \mathbf{u_{m}}\}$ and represents the set of all linear combinations > $$x_{1}\mathbf{u_{1}}+x_{2}\mathbf{u_{2}}+\dots+x_{m}\mathbf{u_{m}}$$ > where $x_{1}, x_{2},\dots, x_{m}$ can be any real numbers Span represents all points in n-dimensional space that a set of vectors could reach when combined in a certain linear combination. if $\text{span}\{\mathbf{u}_{1}, \mathbf{u}_{2}, \dots, \mathbf{u}_{m}\} = \mathbf{R^n}$ then the vectors $\{\mathbf{u}_{1}, \mathbf{u}_{2}, \dots, \mathbf{u}_{m}\}$ spans $\mathbf{R}^n$ In three dimensions the span of two vectors can be visualized by the plane containing both of them. Any point on this plane can be reached by a linear combination of the vectors but any other point that does not lie on the plane cannot. An augmented matrix can be used to find if a point $(a,b,c)$ can be reached by a set of vectors $$\mathbf{u}_{1}=\begin{bmatrix}1 \\ 2 \\ 3\end{bmatrix}, \mathbf{u}_{2}=\begin{bmatrix}4 \\ 5 \\ 6\end{bmatrix}, \mathbf{u}_{3}=\begin{bmatrix}7 \\ 8 \\ 9\end{bmatrix}, \mathbf{v}=\begin{bmatrix}a \\ b \\ c\end{bmatrix} \implies \begin{bmatrix} 1 & 4 & 7 & a \\ 2 & 5 & 8 & b \\ 3 & 6 & 9 & c\end{bmatrix} = \begin{bmatrix}\mathbf{u}_{1} & \mathbf{u}_{2} & \mathbf{u}_{3} & \mathbf{v}\end{bmatrix}$$ Based on this the point $\mathbf{v}$ can only be reached by $\mathbf{u}_{1}, \mathbf{u}_{2}, \dots, \mathbf{u}_{m}$ if the augmented matrix $$\begin{bmatrix} \mathbf{u}_{1} & \mathbf{u}_{2} & \dots & \mathbf{u}_{m} & \mathbf{v} \end{bmatrix}$$ has a solution for the set of vectors $\mathbf{u}_{1}, \mathbf{u}_{2}, \dots, \mathbf{u}_{m}$ in $\mathbf{R}^n$ if $m [!abstract] Definition > Let $\mathbf{a}_{1}, \mathbf{a}_{2}, \dots, \mathbf{a}_{m}$ be vectors in $\mathbf{R}^n$. If > $$A = \begin{bmatrix} > \mathbf{a}_{1} & \mathbf{a}_{2} & \dots & \mathbf{a}_{m} > \end{bmatrix} \quad \text{and} \quad \mathbf{x} = \begin{bmatrix} > x_{1} \\ x_{2} \\ \vdots \\ x_{m} > \end{bmatrix}$$ > then $A\mathbf{x} = x_{1}\mathbf{a}_{1} + x_{2}\mathbf{a}_{2} + \dots + x_{m}\mathbf{a}_{m}$ (only if the number of columns of $A$ equals the number of components of $\mathbf{x}$) This means that $A\mathbf{x}$ is the linear combination of the columns of $A$ where the scalars are the components of the vector $\mathbf{x}$. This is useful to represent vector equations in a more compact way in the form $A\mathbf{x} = \mathbf{b}$ $$A\mathbf{x}=\mathbf{b} \quad \sim \quad x_{1}\mathbf{a}_{1} + x_{2}\mathbf{a}_{2}+\dots+x_{m}\mathbf{a}_{m}=\mathbf{b} \quad \sim \quad \begin{flalign} a_{11}x_{1} + a_{12}x_{2} + \dots + a_{1m}x_{m} = b_{1} \\ a_{21}x_{1} + a_{22}x_{2} + \dots + a_{2m}x_{m} = b_{2} \\ \vdots \ \\ a_{n1}x_{1} + a_{n2}x_{2} + \dots + a_{nm}x_{m} = b_{n} \end{flalign}$$ > [!example] Example > if $\mathbf{a}_{1} = \begin{bmatrix}10 \\ 5 \\ 7\end{bmatrix}, \ \mathbf{a}_{2} = \begin{bmatrix}8 \\ 6 \\ -1\end{bmatrix}, \ \mathbf{x} = \begin{bmatrix}x_{1} \\ x_{2}\end{bmatrix}, \ \mathbf{b} = \begin{bmatrix}18 \\ 31 \\ 3\end{bmatrix}$ then > $$A = \begin{bmatrix} > \mathbf{a}_{1} & \mathbf{a}_{2} > \end{bmatrix} = \begin{bmatrix} > 10 & 8 \\ 5 & 6 \\ 7 & -1 > \end{bmatrix}$$ > We can use these vectors to represent the linear system of equations $A\mathbf{x} = \mathbf{b}$ which when expanded is > $$\begin{gather} > 10x_{1} + 8x_{2} = 18 \\ 5x_{1} + 6x_{2} = 31 \\ 7x_{1} - x_{2} = 3 > \end{gather}$$