#rs/class/math163 #math - - - ## Operations ### Addition $$\vec{u} + \vec{v} = $$ ### Subtraction $$\vec{u} - \vec{v} = $$ ### Dot Product $$\vec{u} \cdot \vec{v} = $$ ### Magnitude $$||\vec{u}|| = \sqrt{ u_{1}^2 + u_{2}^2}$$ ### Unit Vector $$ unit_u=\frac{\vec{u}}{||\vec{u}||}$$ Used to find the vector of magnitude 1 in the same direction as $u$ ### Cross Product $$a \times b = \begin{vmatrix} i&j&k\\a_1&a_2&a_3\\b_1&b_2&b_3\end{vmatrix}= i(a_2b_3-a_3b_2)-j(a_1b_3-a_3b_1)+k(a_1b_2-a_2b_1)$$ Used to create a vector that is orthogonal to both $a$ and $b$. To find what direction it will point in use the right-hand rule (thumb, pointer and middle finger). The cross product is calculated by finding the [[Determinant of a Matrix|determinant]] of the matrix formed in the equation above with the unit vectors in the top row. Properties: - Not commutative $$u\times v \ne v \times u$$ - Anti-commutative $$ u \times v = -(v \times u) $$ - On self $$ a \times a = 0 $$ The magnitude of the cross product of two vectors can be found with $$||u \times v|| = ||u|| * ||v|| * \sin(\theta)$$ The magnitude of the cross product is equal to the area of the parallelogram formed with two adjacent sides as the vectors. ### Projection $$proj_{u}v=\frac{u\cdot v}{\left|\left|u\right|\right|^{2}}u$$ Used to project vector $v$ onto $u$ ![[VectorProjection.excalidraw]] ### Triple Scalar Product Find the Determinant of: $$u * (v \times w) = \begin{vmatrix} u_{1} && u_{2} && u_{3} \\ v_{1} && v_{2} && v_{3} \\ w_{1} && w_{2} && w_{3} \end{vmatrix}$$ The triple scalar product can also be found by finding the cross product of $v$ and $w$ and then taking the dot product of the resulting vector and $u$. $$u * (v \times w) = (u \times v) * w $$ The triple scalar product is equal to the volume of the parallelpiped where each vector represents one adjacent edge.